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x^2-106x+2025=0
a = 1; b = -106; c = +2025;
Δ = b2-4ac
Δ = -1062-4·1·2025
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-106)-56}{2*1}=\frac{50}{2} =25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-106)+56}{2*1}=\frac{162}{2} =81 $
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